The motion of a particle of mass m is describe by y = u t + 2 1 g t 2. Find the force acting on the particle.
y = ut + 1/2 gt2. dy/dt = d/dt ut + d/dt 1/2 gt2. v= u + 2gt. dv/dt = d/dt u + d/dt 2gt. a = 0 + 2g. a = 2g. acceleration of particle =a =2g. mass of particle = m [Given] Force = mass * acceleration.
Force on the particle having mass m is. F = ma. where a is the acceleration. as motion of the particle is. y = u t + 1 2 g t 2. v e l c o c i t y ( v) = d y d t v = u + 2 2 g t v = u + g t a = d v d t = 0 + g a = g. Hence force on the particle is F = mg which is equal to its weight. This conversation is already closed by Expert.
Motion of a particle of mass m is described by y=ut +1/2gtsq .find the force acting on particle. See Attachment.
If motion of a particle of mass (m) is given by y=ut+1/2gt^2 (square).find force acting on it Physics HELP 1.If a particle moves in a plane so that its position is described by the functions x=A*cos(wT) and y=A*sin(wT), the particle is ( w-angular velocity, T-period) A) moving with constant speed along a circle B) moving with a varying speed along a circle, 10/5/2012 · If motion of a particle of mass (m) is given by y=ut+1/2gt^2 (square).find force acting on it, Q.78 The motion of a particle of mass m is described by y=ut+ 1/2gt 2 Find the force acting on the particle . Answer: We have y=ut+ 1/2gt 2 Velocity, Acceleration, F=ma=mg Thus the given equation describes the motion of a particle under acceleration due to gravity and y is the position coordinate in the direction of g.
We can now write the set of three equations in the vector form:, and. where h is the displacement of the body. Problem: The motion of a particle is described by the equation u = at. The distance travelled by the particle in the first 4 second. Solution: Because for the motion u = at. So acceleration is uniform which is equal to a.
11/6/2011 · for this question, you can just use the equation . x’ = xo +vot + .5at^2. x’ = final displacement (which will be zero for this problem since it hits the ground) xo = initial displacement (6m) vo = initial velocity (0m/s also, since the vertical motion is 0. the horizontal motion is still 61m/s, but that doesn’t pertain to this question. t = time, Then solve for v as a function of t.. v = v 0 + at [1]. This is the first equation of motion .It’s written like a polynomial — a constant term (v 0) followed by a first order term (at).Since the highest order is 1, it’s more correct to call it a linear function.. The symbol v 0 [vee nought] is called the initial velocity or the velocity a time t = 0.It is often thought of as the first …
